Message #3055

From: Melinda Green <melinda@superliminal.com>
Subject: Re: [MC4D] The 2c piece
Date: Fri, 23 Jan 2015 22:38:44 -0800

Yes, well that is a rather important detail! :-)
Hopefully Roice or another 5D solver will answer.

On 1/23/2015 7:54 PM, ‘NDCuber .’ alvin5553@gmail.com [4D_Cubing] wrote:
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> oh, I forgot to mention that I was talking about the 5D Cube…
>
> On Fri, Jan 23, 2015 at 7:47 PM, Melinda Green
> melinda@superliminal.com <mailto:melinda@superliminal.com> [4D_Cubing]
> <4D_Cubing@yahoogroups.com <mailto:4D_Cubing@yahoogroups.com>> wrote:
>
> Hello Alvin,
>
> First, there are no 5-color pieces in 4D; only 1C through 4C. The
> 1C pieces are the ones at the very center of the faces, and do not
> have neighbors by definition. They cannot be twisted, but they do
> rotate in place whenever you twist about any other pieces. The way
> to think about all twists is that you highlight any non-central
> sticker on a face, and imagine a ray that starts from the center
> sticker of that face and passes through the highlighted sticker.
> This defines the axis that will be twisted about if you click left
> or right.
>
> I hope that helps,
> -Melinda
>
> On 1/22/2015 7:00 PM, alvin5553@gmail.com
> <mailto:alvin5553@gmail.com> [4D_Cubing] wrote:
>>
>> So when you turn of the 3c, 4c, and 5c pieces, you have this
>> center section where it’s full of stickers. I’ve found out that
>> the outermost sticker of that center section and the innermost
>> sticker are the same piece, but I can’t turn that piece. If you
>> count from the outermost sticker and go inside, the sixth sticker
>> is the innermost 2c piece that can be turned. so how am I suppose
>> to solve that piece?
>>
>>
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