Message #3406

From: Roice Nelson <roice3@gmail.com>
Subject: Re: [MC4D] 3^4 parity?
Date: Tue, 28 Jun 2016 23:23:28 -0500

My apologies, but I’m confused because 1C pieces can’t be permuted. Did
you perhaps mean solving 2C, then 3C, then 4C layer-by-layer? I’m guessing
that you need a sequence to swap two 3C pieces on the final layer, without
worrying about 4C pieces. A screenshot would be helpful.

On Tue, Jun 28, 2016 at 5:37 AM, Andy F legomany3448@gmail.com [4D_Cubing] <
4D_Cubing@yahoogroups.com> wrote:

>
>
> Sorry, I forgot to mention my method. I solve layer-by-layer: 1c pieces of
> the first layer, then 2c, then 3c, then the 2c pieces of the second layer,
> then the 3c pieces of the second layer. The last layer requires six steps,
> consisting of orientation and permutation of the three types of pieces.
> Usually I orient all pieces first, then permute the 1c, 2c, and 3c pieces
> respectively, though it’s possible to solve 3c before 2c. In this case, I
> had oriented the entire last layer, and was almost done permuting the 2c
> pieces, while the 3c pieces were still unsolved (oriented, though). If
> you’re curious I can supply a screenshot or log file.
>
> –
>
> I’d love to change the world, but they haven’t released the source code
> yet.
>
>
>
>