Message #4173

From: Alvin Yang <alvin5553@gmail.com>
Subject: Re: [MC4D] 5D parity ?
Date: Mon, 17 Dec 2018 16:42:39 -0500

On Mon, Dec 17, 2018, 4:40 PM Alvin Yang <alvin5553@gmail.com> wrote:

> Hi Henri!
>
> I believe I have a clue about what your issue is, but I can’t be too sure.
> Next time, maybe post a screenshot of your issue. Based on what you’ve
> described, the problem seems to be a swapping permutation of pieces
> belonging to the same cell (well, hypercell anyway). In the screenshot
> below, on the 4D Cube, I’ve tried to create something that seems to match
> what you’re describing, where two pieces are swapped in terms of
> permutation on the same cell. If that’s similar to the issue you’re dealing
> with, I have also attached a video showing how I resolved my particular 2c
> swapping issue. Hope this helps any bit.
>
> Alvin
> [image: image.png]
>
> On Mon, Dec 17, 2018, 3:07 PM henrikengebretsen@gmail.com [4D_Cubing] <
> 4D_Cubing@yahoogroups.com> wrote:
>
>>
>>
>> Hello all!
>>
>>
>> It’s been a couple years since I first solved both the 3^4 and the 5^4,
>> and just recently I thought I should take on the daunting challenge that is
>> the 3^5.
>>
>> Holy mother, my brain. It hurts.
>>
>> Anyway, I have a problem that I can’t for the life of me figure out.
>>
>>
>> Basically, I have managed to solve all the 2-sticker pieces, apart from 2.
>>
>> I.e. the yellow-red needs to swap with the yellow-blue.
>>
>> I know this is impossible on the 3^3, and to the best of my knowledge
>> it’s not possible on the 3^4 either (though I might be wrong on that one).
>>
>>
>> My question to you all is how would I go about fixing this? Is this a
>> parity case?
>>
>> I feel like there’s a very trivial solution, but my brain is fried..
>>
>>
>> Thanks!
>>
>>
>>
>