Message #1525

From: Andrey <>
Subject: [MC4D] Re: new hemi-cube and hemi-dodecahedron puzzles
Date: Tue, 08 Mar 2011 06:15:38 -0000

Okay. Take regular tetrahedron and group of it’s movements (A4). Its fundamental area is 1/3 of tetrahedron face, like in this pucture:
May be we can do something from set of tiles that are invariant to A4? Of course, verices should not be included in movement (or they may be centers of special faces), but otherwise I don’t see any problems…


— In, Roice Nelson <roice3@…> wrote:
> >
> > On Mon, Mar 7, 2011 at 3:09 PM, Andrey wrote:
> >
> >> If you twist opposite sides in same direction (relative to sphee surface),
> >> you’ll get orientable puzzle. I don’t know, if there are sphere paintings
> >> that are invariant to this transformation (i.e. order of adjacent colors of
> >> all intances of one face is the same). There is 5-color painting if
> >> icosahedron (all faces of outscribed tetrahedra have the same color), but
> >> I’m not sure that it will work.
> >
> >
> Here is something else interesting I realized about the
> "orientable hemi-cube" we’ve been talking about… In order for twists to
> move in the same direction relative to the surface, and for it to still be
> interpreted as a hemi-cube puzzle, the identification of 2C/3C piece pairs
> must change after every twist! Without allowing this kind of wackiness,
> which honestly doesn’t feel legit at all, I think the answer to Andrey’s
> question about the existence of orientable periodic paintings for the sphere
> is provably ‘no’ for any tiling on the sphere (regular, uniform, whatever).
> Here is how the logic showing that could go… If an orientable painting was
> possible, we are talking about choosing a subset of tiles, which when
> repeated would cover the sphere (the "universal cover" of the chosen subset
> would be the sphere). The topology of the surface represented by this
> subset of tiles must admit elliptical geometry, but there are only two
> topologies which do so, the sphere and the projective plane (see chapter 12
> of Jeff Weeks’ "The Shape of
> Space<>").
> The latter is non-orientable, so the topology of our subset must be the
> sphere. However, the universal cover of the sphere is the sphere itself
> (see here <>), so the the
> only set of tiles which will work is the full set of tiles, which already
> covers the entire sphere. So there is no periodic painting possible.
> Also, I have fixed the issue Nan found with the even-length hemi-cube
> puzzles, and uploaded a new version. Thank you again Nan!
> Roice